`int(dx)/((e^x-1)^2)`

(i) int (dx)/(e^x+e^(-x)) (ii) int e^x/(e^(2x)+1) dx

int(dx)/(e^(x)(e^(x)+1)^(2))

int(dx)/(sqrt(e^(2x)-1))=

int(dx)/(1+e^((x)/(2)))

STATEMENT-1 : int(dx)/(e^(x)+e^(-x)+2)=-(1)/(e^(x)+1)+c and STATEMENT-2 : int(d(f(x)))/((f(x))^(2))=-(1)/(f(x))+c

If int(dx)/(sqrt(e^(x)-1))=2tan^(-1)(f(x))+C , (where x gt0 and C is the constant of integration ) then the range of f(x) is

int(e^(x))/((e^(x)-1)(e^(x)+2))dx=

Evaluate int(dx)/(sqrt(1+e^(x)+e^(2x)))

Integration of other transcendental functions I=int(e^(x)dx)/((1+e^(2x))^(2)).