If `I_(0)` is the moment of inertia body about an axis passing through its center of mass. The moment about a parallel axis and at distance `d` is `I=I_(0)+Md^(2)`. The variation of `I` with `d` is

Assertion: Moment of inertia of a rigid body about any axis passing through its centre of mass is minimum Reason: From theorem of parallel axis I=I_(cm)+Mr^(2)

If the moment of inertia of a ring about transverse axis passing through its centre is 6 kg m^(2) , then the M.I. about a tangent in its plane will be

The moment of inertia of a solid sphere about an axis passing through the centre radius is 1/2MR^(2) , then its radius of gyration about a parallel axis t a distance 2R from first axis is

Moment of inertia of a disc about its own axis is I. Its moment of inertia about a tangential axis in its plane is

The moment of inertia of a ring of mass 5 gram and radius 1 cm about and axis passing through its edge and parallel to its natural axis is

The moment of inertia of ring about an axis passing through its diameter is I . Then moment of inertia of that ring about an axis passing through its centre and perpendicular to its plane is

The moment of inertia of a solid sphere about an axis passing through its centre of gravity is (2)/(5)MR^(2) . What is its radius of gyration about a parallel axis at a distance 2R from the first axis ?

Moment of inertia of a rigid body about an axis passing through its centre of mass is I_(0) and moment of inertia of the same body about another axis parallel to the first axis is I. Then

Moment of inertia of a rigid body about an axis through its centre of gravity is 10kg m^(2) . If mass of the body about an axis parallel to the first axis and separated by a distance of 1m is