A tunnel is dug inside the earth across one of its diameters. Radius of earth is `R` and its mass is `M`. A particle is projected inside the tunnel with velocity `sqrt((2GM)/(R))` from one of its ends then maximum velocity attained by the particle in the subsequent motion is (assuming tunnel to be frictionless)

A tunnel is dug inside the earth across one of its diameters. Radius of earth is R and its mass is M. A particle is projected inside the tunnel with velocity sqrt((2GM)/(R)) from one of its ends then maximum velocit attained by the particle in the subsequent motion is sqrt((nGM)/(R)) (assuming tunnel to be frictionless). Find n

A particle is projected vertically upward with with velocity sqrt((2)/(3)(GM)/(R )) from the surface of Earth. The height attained by it is (G, M, R have usual meanings)

A particle is projected from earth surface with a velocity sqrt((4gR)/(3)) in upward direction where R is the radius of earth. Find the velocity of particle when it is at half its maximum height.

When a particle is thrown vertically upwards, its velocity at one third of its maximum height is 10sqrt2m//s . The maximum height attained by it is

A tunnel is dug across the diameter of earth. A ball is released from the surface of Earth into the tunnel. The velocity of ball when it is at a distance (R )/(2) from centre of earth is (where R = radius of Earth and M = mass of Earth)

A tunnel is dug in the earth across one of its diameter. Two masses m and 2m are dropped from the two ends of the tunel. The masses collide and stick each other. They perform SHM , the ampulitude of which is (R = radius of earth)

A satellite is orbiting around earth in a circular orbit of radius r . A particle of mass m is projected from satellite in forward direction with velocity v=sqrt(2/3) times orbital velocity (this velocity is with respect to the earth). During subsequent motion of the particle, its minimum distance from the centre of earth is

A particle of mass m is projected upwards with velocity v=(v_(e))/(2) , where v_(e) is the escape velocity then at the maximum height the potential energy of the particle is : (R is radius of earth and M is mass of earth)

A body is projected up with a velocity equal to sqrt((9GM)/(8R)) , where M is the mass of the earth and R is the radius of the earth. The maximum distance it reaches from the centre of the earth is