If the intensity of incident radiation on a metal surface is doubled, what happens to the kinetic energy of the electrons emitted?

If the intensity of incident radiataions on a metal is doubled, what happens to the K.E. of electrons emitted.

If intensity of radiation falling on metal surface is doubled, what happens to K.E. of electron emitted?

Assertion: If the intensity of incident radiation on a metal is doubled, then K.E. of photoelectrons emitted will be doubled. Reason: K.E.=1/2mv^2=h(v-v_0), where v is the velocity of photo electrons.

Assertion: If the intensity of incident radiation on a metal is doubled, then K.E. of photoelectrons emitted will be doubled. Reason: K.E.=1/2mv^2=h(v-v_0), where v is the velocity of photo electrons.

State the influence of work function on kinetic energy of electrons emitted in a photocell. If the intensity of the incident radiation is doubled, what changes occur in the stopping potential and photoelectric current?

State the dependence of work function on kinetic energy of electrons emitted in a photocell. If the intensity of the incident radiation is doubled, what changes occur in the stopping potential and photoelectric current?