If `x/sqrt4=sqrt16` then `x=`

If sqrtx= sqrt3-sqrt5 , then the value of x^2-16x+6 is : यदि sqrtx= sqrt3-sqrt5 , x^2-16x+6 का मान ज्ञात करें :

If x= (4sqrt(15))/(sqrt5+sqrt3) , then (x+sqrt(20))/(x-sqrt(20))+(x+sqrt(12))/(x-sqrt(12))= ?

If sqrt(19-4sqrt(x))=sqrt(12)-sqrt(7), then x=..

Let f (x) is a real valued function defined on R such that f(x) = sqrt(4+sqrt(16x^2 - 8x^3 +x^4)) . The number of integral values of 'k' for which f(x) =k has exactly 2 distinct solutions for k in [0,5] is

If , 4x = sqrt5+2 , then the value of (x-1/(16x)) is

If sqrt(x)+sqrt(x-sqrt(1-x))=1 , then show that x=(16)/(25) .

If sqrt(x)-sqrt(12)=sqrt(4)-sqrt(x) , then find x .