if `logx/(l+m-2n)=logy/(m+n-2l)=logz/(n+l-2m)` then `xyz=`

(log x)/(l+m-2n)=(log y)/(m+n-2l)=(log z)/(n+l-2m)

Subtract: 3l(l-4m+5n) ,4l(10n-3m+2l)

Subtract: 3l(l-4m+5n) om 4l(10n-3m+2l)

Subtract: 3l\ (l-4m+5n) from 4l(10 n-3m+2l)

Subtract : 3l(l - 4m + 5n) from 4l(10n - 3m + 2l)

|[(m+n)^(2), l^(2), mn], [(n+l)^(2), m^(2), ln], [(l+m)^(2), n^(2), lm]| =(l^(2) +m^(2) +n^(2))(l-m)(m-n)(n-l)(l+m+n)