The rate of a certain reaction depends on concentration according to the equation:
`(-dC)/(dt)=(K_(1)C)/(1+K_(2)C)`.
What will be the order of reaction, when concentration (C ) is:
(a) very-very high?
(b) very-very low?

The rate of decomposition of ammonia is found to depend upon the concentration of ammonia as : -(d[ NH_3])/(dt)= (k_1 [NH_3])/(1+ k_2[NH_3]) what will be the order of reaction when : concentration of NH_3 is very high ?

The rate of decomposition of amnionia is found to depend upon the concentration of NH_{3} according to the equation -d[NH_{3}]/dt = K_{1}[NH_{3}]/1_{+K_{2}[NH_{3}] What is the order of the reaction when i) concentration of NH_{3} is very high ii) concentratiod of NH_{3} is'verý

Very low concentrations of SO_(2) acts as

The reaction A + 2B rarr C obeys the rate equation. Rate = K[A]^((1)/(2))[B]^((3)/(2)) What is the order of the reaction ?

Very low concentrations of SO_2 acts as

The reaction A +3B to 2C obeys the rate equation Rate =k [A]^(1//2) [B]^(3//2) What is the order of the reaction ?