Given that the standard reduction potential `(E^(@))` of `Cr^(3+) | Cr` and `Cr^(2+) |Cr` are -0.74 and -0.91 V respectively. The `E^(@)` of `Cr^(3+) |Cr^(2+)` is:

The standard reduction potentials of Ni^(2+)|Ni, Cr^(3+)|Cr, Ag^(+)|Ag, Fe^(2+)|Fe electrodes are -0.24, -0.74, +0.80 and -0.44V , respectively. Arrange Ni, Cr, Ag and Fe in increasing order of their reducing power and give reasons.

E^(c-) for Cr^(3+)+3e^(-) rarr Cr and Cr^(3+)+e^(-) rarr Cr^(2+) are -0.74 V and -0.40V , respectively, E^(c-) for the reaction is Cr^(+2)+2e^(-) rarr Cr

E^(c-) for Cr^(3+)+3e^(-) rarr Cr and Cr^(3+)+e^(-) rarr Cr^(2+) are -0.74 V and -0.40V , respectively, E^(c-) for the reaction is Cr^(+2)+2e^(-) rarr Cr

Given E ^(@)(Cr ^(3+)|Cr)=-0.72V and E ^(@)(Fe ^(2+)|Fe)=-0.42 V. The potential for the cell Cr |Cr ^(3+) (0.1M)||Fe ^(2+) (0.01M) |Fe is

If E_(1)=0.5V corresponds to Cr^(3)+3e^(-)rarr Cr_((s)) and E_(2)=0.41V corresponds to Cr^(3+)+e rarr Cr^(2+) reactions, calculate the emf (E_(3)) of the reaction Cr^(2+)+e rarr Cr^(2+) reactions, calculate the emf (E_(3)) of the reaction Cr^(2+)+2e rarr Cr_((s))