If the velocity of a particle moving along x-axis is given as `v=(3t^(2)-2t)` and t=0, x=0 then calculate position of the particle at t=2sec.

If the velocity of a paraticle moving along x-axis is given as v=(4t^(2)+3t=1)m//s then acceleration of the particle at t=1sec is :

If the velocity of a paraticle moving along x-axis is given as v=(4t^(2)+3t=1)m//s then acceleration of the particle at t=1sec is :

If the velocity of a paraticle moving along x-axis is given as v=(4t^(2)+3t=1)m//s then acceleration of the particle at t=1sec is :

If the velocity of the a particle moving on x-axis is given by v=3t^(2)-12 t +6. at what time is the acceleration of particle zero ?

Position of particle moving along x-axis is given as x=2+5t+7t^(2) then calculate :

Position of particle moving along x-axis is given as x=2+5t+7t^(2) then calculate :

Position of particle moving along x-axis is given as x=2+5t+7t^(2) then calculate :

v_(x) is the velocity of a particle moving along the x-axis as shown in the figure. If x=2.0m at t=1.0s, what is the position of the particle at t=6.0s ?

The position of the particle moving along x-axis is given by x=2t-3t^(2)+t^(3) where x is in mt and t is in second.The velocity of the particle at t=2sec is

V_(x) is the velocity of a particle of a particle moving along the x- axis as shown. If x=2.0m at t=1.0s , what is the position of the particle at t=6.0s ?