A chain consisting of `5` links each of mass d `0.1 kg` is lifted vertically up with a constant acceleration of `2.5m//s^(2)`.The force of interaction between `1st` and `2nd` links as shown

A chain consisting of 5 links each of mass 0.1 kg is lifted vertically up with a constant acceleration of 2.5m//s^2 . The force of interaction between 1st and 2nd links as shown:

A chain consisting of 5 links each of mass 0.1 kg is lifted vertically up with a constant acceleration of 2.5m//s^2 . The force of interaction between 1st and 2nd links as shown:

A chain consisting of 5 links each of mass 0.1 kg is lifted vertically with a constant acceleration of 2.5 m//s^(2) as shown in the figure. The force of interaction between the top link and the link immediately below it, will be

A chain consisting of 5 links each of mass 0.1kg is lifted vertically with a constant acceleration of 2m//s^(2) as shown in The force of interaction (in newton) between the top link and the link immediately below it will be Take g = 10m//s^(2) .

A chain consists of five links each with mass 100gm as shown. It is lifted vertically upward with a constant acceleration of 2ms^(-2) .Then the force F exerted by the agent in lifting the chain is 'x'N. Then x is ...........

A chain consists of five links each with mass 100gm as shown. It is lifted vertically upward with a constant acceleration of 2ms^(-2) .Then the force F exerted by the agent in lifting the chain is 'x'N. Then x is ...........