A lift starts from rest with a constant upward acceleration It moves 1.5 m in the first 0.4 A person standing in the lift holds a packet of 2 kg by a string Calculate the tension in the string during the motion .

A lift starts from rest with constant upward acceleration . It moves 1.5m in the first 0.4 secs. A person standing in the lift hold a packet of 2 kg by a string. Calculate the tension in the string during the motion.

An elevator starts from rest with a constant upward acceleration. It moves 5 m in the first 2 s. A passenger in the elevator is holding a 4 kg package by a vertical string. Find the tension in the string during the acceleration process in N.

An elevator starts from rest with a constant upward acceleration it moves 2m in the first 0.6 second. A passenger in the elevator is holding a 3 kg package by a vertical string When the elevator is moving What is the tension in the string?

An elevator starts from rest with a constant downward acceleration and covers 2.5m in first second If the lift weighs 200kg what would be the tension in the ropes of the lift ?

A lift of mass 200 kg is moving upward with an acceleration of 3m//s^(2) . If g=10 m//s^(2) then the tension of string of the lift will be :

A lift of mass 200 kg is moving up with an acceleration of 4 m cdot s^(-2) . What is the tension in the lift cable? If the lift moves down with the same acceleration, what will be the tension in that case? [ g = 9.8 m cdot s^(-2) ]

A lift moving up with an acceleration equal to 1/2th of that due to gravity. What is the apparent weight of a 80 kg man standing in the lift?

The mass of man when standing on the lift is 60 kg. The weight when the lift is moving upwards with acceration 4.9 ms^(-2) is