Find the work performed by one mole of a Van der Walls gas during its isothermal expansion from the volume `V_1` to `V_2` at a temperature `T`.

Find the entropy increment of one mole of a Van der Waals gas due to the isothermal variation of volume from V_1 to V_2 . The Van der Walls corrections are assumed to be known.

What is an isothermal process? State essential conditions for such a process to take place. Show analytically that work done by one mole of an ideal gas during isothermal expansion from volume V_1 to volume V_2 is given by = "RT log"_(e) V_2/V_1 . What is the change in internal energy of a gas, which is compressed isothermally?

What is an isothermal process? State essential conditions for such a process to take place. Show analytically that work done by one mole of an ideal gas during isothermal expansion from volume V_1 to volume V_2 is given by = "RT log"_(e) V_2/V_1 . What is the change in internal energy of a gas, which is compressed isothermally?

Find the expression for the work done by a system undergoing isothermal compression (or expansion) from volume V_(1) to V_(2) at temperature T_(0) for a gas which obeys the van der waals equation of state. (P +an^(2) //V^(2)) (V-bn) =nRT ?

Find the expression for the work done by a system undergoing isothermal compression (or expansion) form volume V_(1) to V_(2) at temperature T_(0) for a gas which obeys the van der wattws equation of state. (P +an^(2) //V^(2)) (V-bn) =nRT ?

An ideal gas undergoes isobaric expansion at pressure P from volume V_1 to V_2 the work done is :

What is the relation for work done (i) reversibly and (ii) irreversibly for the isothermal expansion of an ideal gas from volume V_(1) to V_(2) at temperature T?

When a van der waals ' gas undergoes free expansion , then its temperature

The equation of state of a gas is given as P(V-b)=nRT, where b is constant ,n is the number of moles and R is the universal gas constant .when 2 moles of this gas undergo reversible isothermal expansion from volume V to 2V ,what is work done by the gas ?