The resistance of a galvanometer is `100Omega`. A shunt of `5 Omega` is connected to it to convert it into an ammeter. The internal resistance of the ammeter is

If the galvanometer current is 10 mA, resistance of the galvanometer is 40 Omega and shunt of 2 Omega is connected to the galvanometer, the maximum current which can be measured by this ammeter is

If the galvanometer current is 10 mA, resistance of the galvanometer is 40 Omega and shunt of 2 Omega is connected to the galvanometer, the maximum current which can be measured by this ammeter is

A battery of EMF 1.4 V and internal resistance 2Omega is connected to resistor of 100Omega resistance through an ammeter. The resistance of the ammeter is (4)/(3)Omega . A voltmeter is also connected to find potential difference across resistor. The ammeter reacds 0.02 A if resistance of voltmeter is 100x then x is

A galvanometer has a resistance of 16 Omega and gives a full scale deflection, when a current of 20 mA is passed through it. The only shunt resistance available is 0.04 Omega which is not appropriate to convert galvanometer into an ammeter. How much resistance should be connected in series with coil of galvanometer so that the range of ammeter is 10 A?

A cell has an emf of 3 volt and internal resistance 2Omega . It is connected to an ammeter having resistance 2Omega and to an external resistance of 100Omega . When a voltmeter is connected across the 100Omega . Resistance, the ammeter reading is 40 mA. The resistance of the voltmeter is