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Sn=3/(1^2)+3/(1^2+2^2)+7/(1^2+2^2+3^2)+ ...

`S_n=3/(1^2)+3/(1^2+2^2)+7/(1^2+2^2+3^2)+` upto `n` terms, then `S_n=(6n)/(n+1)` b. `S_n=(6(n+2))/(n+1)` c. `S_oo=6` d. `S_oo=1`

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RESONANCE DPP-JEE MAINS-All Questions
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