The equation of the normal to the curve `y=sin x` at the point `(pi,0)` is:
O `x+y=pi`
O `x+y+pi=0`
O `x-y=pi`
O `x-y+n=0`

The equation of the normal to the curve y=x+sin x cos x " at " x=(pi)/(2), is

Write the equation of the normal to the curve y=x+sinxcosx at x=pi/2 .

The equation of a normal to the curve,sin y=x((sin pi)/(3)+y) at x=0 is

Find the equation of the normal to the curve y = (sin 2x + cot x + 2)^(2) " at " x = (pi)/(2)

The equation of normal to the curve y=sqrt(2) sin (2x+(pi)/(4))" at "x=(pi)/(4) is

Find the equations of tangent and normals to the curves y=sin x+cos x at x=(pi)/(3)

The equation of the normal to the curve x=a\ cos^3theta,\ \ y=a\ s in^3theta at the point theta=pi//4 is x=0 (b) y=0 (c) x=y (d) x+y=a

The area of the region bounded by the curve y=x"sin"x, x-axis, x=0 and x=2pi is :