`int_(-1)^(1)(x^(2)-2x+3)dx`

int_(-1)^(1)3x^(2)dx

Evaluate int_(1)^(3)(x^(2)-2x)dx

Evalaute int_(-1)^(1)(x^2-3x+2)dx

Evaluate int_(-1)^(1)(x^2-3x+2)dx

int_(1)^(4)(3x^(2)+2x)dx

Evaluate int_(1)^(3)|x^(2)-2x|dx

int_(1)^(3)(2x^(2)+5x)dx

show that (a) int_(0) ^(2pi) sin ^(3) x dx = 0 , (b) int_(-1)^(1) e^(-x^(2)) dx = 2 int_(0)^(1) e^(-x^(2)) dx

int_(-1)^(2)|x^(3)-x|dx

int_(0)^(2)(3x^(2)+2x-1)dx=