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On passing 0.5 mool of electrons through...

On passing `0.5 mool` of electrons through `CuSO_(4)` and `Hg_(2)(NO_(3))_(2)` solutions in series using inert electrodes

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On passing 0.5 mole of electrons through CuSO_(4) and Hg_(2)(NO_(3))_(2) solutions in series using inert electrodes

A solution containing 1 mol per litre of each Cu(NO_(3))_(2), AgNO_(3), and Hg_(2)(NO_(3))_(2) is being electrolyzed by using inert electrodes. The values of standard electrode potentials in volts ( reduction potential ) are Ag|Ag^(o+)=+0.80, 2Hg|Hg_(2)^(2+)=+0.79 Cu|Cu^(2+)=+0.34,Mg|Mg^(2+)=-2.37 . With increasing voltage, the sequence of deposition of metals at the cathode will be

A solution containing 1 mol per litre of each Cu(NO_(3))_(2), AgNO_(3), and Hg_(2)(NO_(3))_(2) is being electrolyzed by using inert electrodes. The values of standard electrode potentials in volts ( reduction potential ) are Ag|Ag^(o+)=+0.80, 2Hg|Hg_(2)^(2+)=+0.79 Cu|Cu^(2+)=+0.34,Mg|Mg^(2+)=-2.37 . With increasing voltage, the sequence of deposition of metals at the cathode will be

An aqueous solution containing one mole per litre of each Cu(NO_(3))_(2), AgNO_(3),Hg(NO_(3))_(2) is being electrolysed using inert electrodes. The values of standard electrdoe potential in volts (reduction potential) are Ag|Ag^(+)=+0.80 2Hg|Hg^(2+)=+0.79 Cu|Cu^(2+)=+0.34 Mg|Mg^(2+)=-2.37 With increasing voltage, the sequence of deposition of metals on cathode will be

A solution containing one mole per litre of each Cu(NO_(3))_(2), AgNO_(3), Hg_(2)(NO_(3))_(2) is being electrolysed by using inert electrodes. The values of standard electrode potentials in volts (reduction potentials) are Ag^(+)//Ag = +0.80 V, HG_(2)^(2+)//Hg = +0.79 V Cu^(+)//Cu = +0.34 V, Mg^(2+)//Mg = -2.37 V With increasing valtage, the sequence of deposition of metals on the cathode will be

When NH_(4)OH is added in Hg_(2)(NO_(3))_(2) solution, the ppt formed is: