Equation of the normal to the curve `y=-sqrt(x)+2` at the point (1,1)

Equation of the normal to the curve y=-sqrt(x)+2 at the point of its intersection with the curve y=tan(tan-1x) is

Find the equation of the normal to the curve y = x^3 at the point (2,1).

The equation of the normal to the curve 2y+x^(2)=3 at the point (1,1) is

The equation of the normal to the curve y=x(2-x) at the point (2, 0) is

Equations of the tangent and normal to the curve y=3sqrt(x-1) , at the point x=1 , are repectively.

Equation of normal to the curve y^(2)=(x)/(2-x) at the point (1,1) is

Find the equations of tangent and normal to the curve y=x^(2)+3x-2 at the point (1, 2). .

Find the equation of normal to the curve, y = .x^3 at the point (-1.-1).