Express `tan theta` in terms of `tan alpha, if sin (theta + alpha) = cos (theta + alpha)`.

if sin(theta+alpha)=cos(theta+alpha) then tan alpha

cos ( theta + alpha)* cos ( theta - alpha) + sin ( theta + alpha) * sin (theta - alpha )=

If sin theta = nsin(theta +2alpha) then tan(theta + alpha) =

Simplify be reducing to a single term : cos (theta + alpha ) cos ( theta - alpha ) - sin ( theta + alpha ) sin (theta - alpha).

Solution ( Principle & General Solution ) || General form ( tan theta = tan alpha, cos theta = cos alpha , sin theta = sin alpha)

tan theta = (sin alpha-cos alpha) / (sin alpha + cos alpha)

If m sin theta=n sin(theta+2 alpha), then tan(theta+alpha)=

If sin ( theta + alpha ) = cos ( theta + alpha ) , then tan theta =