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(sec 8 A-1)/( sec 4A-1)=...

`(sec 8 A-1)/( sec 4A-1)=`

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Prove that (sec 8A-1)/( sec 4 A -1) = ( tan 8 A)/( tan 2A).

Prove that (sec 8A-1)/(sec 4A-1)=(Tan8A)/(Tan2A)

Prove that (i) (sec 8A -1)/(sec 4A -1) =(tan 8A)/(tan 2A) (ii) (cos A+ sin A)/(cos A - sin A)-(cos A-sin A)/(cos A+sin A)=2 tan 2A

(sec8A-1)/(sec4A-1)=?

(sec8A-1)/(sec4A-1)=

(sec8A-1)/(sec4A-1)=(tan 8A)/(tan2A)

If (sec8A-1)/(sec4A-1)=tanmA.cotnA, then: (m,n)-=....

Prove that (sec8A-1)/(sec4A-1)=(tan8A)/(tan2A)

(sec8A-1)/(sec4A-1) is equal to (A) (tan2A)/(tan8A) (B) (tan8A)/(tan2A) (C) (cot8A)/(cot2A) (D) none of these

(sec8A-1)/(sec4A-1) is equal to (A) (tan2A)/(tan8A) (B) (tan8A)/(tan2A) (C) (cot8A)/(cot2A) (D) none of these