If `cos A=7/25` and `3pi/2ltAlt2pi` ,then `cot (A/2)=`

If cos A=(7)/(25) and (3 pi)/2ltAlt2pi then cot((A)/(2))

If cosA=7/25and(3pi)/2ltAlt2pi,"then ""cos"A/4+"cos"A/2-cos2A=

If (3pi)/(2)ltAlt2pi and sinA=-7//25 , then

If 7 sin A = 24 cos A and 0ltAlt pi/2 , find 14 tan A - 25 cos A-7 sec A .

The value of cos ((3pi)/2 + x)cos (2pi + x){cot ((3pi)/2 - x) + cot (2pi + x)} is-

cos ((3pi)/(2)+theta) cos (2pi+theta) xx [ cot ((3pi)/(2) -theta) + cot (2pi + theta) ] = ?

Simplify: (cos(2pi + alpha)"cosec" (pi - alpha) tan (pi/2 + alpha))/("sec" (pi/2 + alpha) sin ((3pi)/2 - alpha) cot (2pi - alpha))

cos ((3pi )/( 2 ) + x) cos (2pi + x) [cot ((3pi)/( 2)- x ) + cot (2pi +x) ]=1