If `v=(3hati+2hatj+6k)` m/s and `m=(2)/(7)kg` then find kinetic energy `(i.e. (1)/(2)mv^(2))`

If vecv=(3hati+2hatj+6k) m/s and m=(2)/(7)kg then find kinetic energy (i.e. (1)/(2)mv^(2))

If vecv=(4hati+5hatj+6k) m/s and m=(2)/(7)kg then find kinetic energy (i.e. (1)/(2)mv^(2))

If vecv=(4hati+3hatj+5k) m/s and m=(2)/(7)kg then find kinetic energy (i.e. (1)/(2)mv^(2))

Relation between kinetic energy and momentum Let us consider a body of mass 'm' having a velocity 'v', then momentum of the body P = mass xx velocity P = m xx v rArr v = (P)/(m) " "...(1) From definition, kinetic energy (K.E) of the body K.E = (1)/(2) mv^(2)" "...(2) Now putting the value of (1) in (2) we have K.E = (1)/(2)m ((P)/(m))^(2) K.E. = (1)/(2)m (P^(2))/(m^(2)) = (1)/(2) (P^(2))/(m) = (P^(2))/(2m)" "...(3) Thus we can write P^(2) = 2m xx K.E rArr P = sqrt(2m xx K.E) Thus momentum = sqrt(2 xx "mass" xx "kinetic energy") The kinetic energy of a given body is doubled. Its momentum will

Relation between kinetic energy and momentum Let us consider a body of mass 'm' having a velocity 'v', then momentum of the body P = mass xx velocity P = m xx v rArr v = (P)/(m) " "...(1) From definition, kinetic energy (K.E) of the body K.E = (1)/(2) mv^(2)" "...(2) Now putting the value of (1) in (2) we have K.E = (1)/(2)m ((P)/(m))^(2) K.E. = (1)/(2)m (P^(2))/(m^(2)) = (1)/(2) (P^(2))/(m) = (P^(2))/(2m)" "...(3) Thus we can write P^(2) = 2m xx K.E rArr P = sqrt(2m xx K.E) Thus momentum = sqrt(2 xx "mass" xx "kinetic energy") Two bodies masses 1 kg and 4 kg having equal kinetic energies. The ratio of their momentum is

Relation between kinetic energy and momentum Let us consider a body of mass 'm' having a velocity 'v', then momentum of the body P = mass xx velocity P = m xx v rArr v = (P)/(m) " "...(1) From definition, kinetic energy (K.E) of the body K.E = (1)/(2) mv^(2)" "...(2) Now putting the value of (1) in (2) we have K.E = (1)/(2)m ((P)/(m))^(2) K.E. = (1)/(2)m (P^(2))/(m^(2)) = (1)/(2) (P^(2))/(m) = (P^(2))/(2m)" "...(3) Thus we can write P^(2) = 2m xx K.E rArr P = sqrt(2m xx K.E) Thus momentum = sqrt(2 xx "mass" xx "kinetic energy") Two bodies of mass 1 kg and 4 kg possess equal momentum. The ratio of their kinetic energies is

A body of mass 0.8 kg has intial velocity (3hati-4hatj) ms^(-1) and final velocity (-6hatj+2hatk) ms^(-1) . Find change in kinetic energy of the body?

A body of mass 0.8 kg has intial velocity (3hati-4hatj) ms^(-1) and final velocity (-6hatj+2hatk) ms^(-1) . Find change in kinetic energy of the body?

A particle of mass 2.4kg is having a velocity of (3hati+4hatj)m/s at (5,6)m.The angular momentum of the particle about (1,2)m ,in kgm^(2)/s ,is?