The ends of a quadrant of a circle have the coordinates (1, 3) and (3, 1). Then the center of such a circle is

The extermities of a diameter of a circle have coordinate (-4,-3) and (12,-1). The length of the segment cut off by the circle on y -axis is

Center Q of the circle above has coordinate of (4, 3) . What is the circumference of the circle?

If the coordinate of one end of a diameter of a circle is (3,4) and the coordinates of its centre is (-3,2) then the coordinate of the other end of the diameter is .

The end points of a diameter of a circle are (1,-1) and (3,5). Find the equation of the circle. Also find its centre and radius.

The end points of a diameter of a circle are (1,-1) and (3,5). Find the equation of the circle. Also find its centre and radius.

If ends of a diameter of a circle are (-4,3) and (12,-1) , then y-intercept of the circle is

Point K is the center of the circle above, and the coordinates of Point K are (2, -1). What is the area of the circle?

The coordinates of one end point of a diameter of a circle are (4,-1) and the coordinates of the centre of the circle are (1,-3) . Find the coordinates of the other end of the diameter.

Line 2x+3y+1=0 is a tangent to the circle at (1,-1). This circle is orthogonal to a circle which is drawn having diameter as a line segment with end points (0, -1) and (-2, 3). Then the equation of the circle is

Line 2x+3y+1=0 is a tangent to the circle at (1,-1). This circle is orthogonal to a circle which is drawn having diameter as a line segment with end points (0, -1) and (-2, 3). Then the equation of the circle is