The height of the maximum cone that can be obtained by revolving a right angled triangle of hypotenuse `l `units about a side is
(1)`l/(sqrt(3))` 2) `(1)/(sqrt(2))` 3) `(1)/(3)`4) `2l`

If the product of height and square of the radius of the greatest cone obtained by rotating a right - angle triangle of hypotenuse 2 meters about a side is (k)/(3sqrt3) , then k is equal to

The volume of the greatest cone obtained by rotating a right - angled triangle of hypotenuse 2 units about a side is (kpi)/(9sqrt3) cubic units, then the value of k is equal to

find the volume of the greatest right circular cone that can be described by the revolution about a side of a right angled triangle of hypotenuse 1 ft.

If cos^-1(sqrt3x) and cos^-1 xare two angles of a right angled triangle, then x= (A) 1/sqrt(6) (B) 0 (C) sqrt(3)/2 (D) 1/2

If the sides of a right-angled triangle are in A.P., then the sines of the acute angles are 3/5,4/5 b. 1/(sqrt(3)),sqrt(2/3) c. 1/2,(sqrt(3))/2 d. none of these

If the angles of a triangle are in the ratio 4:1:1, then the ratio of the longest side to the perimeter is sqrt(3):(2+sqrt(3))( b) 1:61:2+sqrt(3)(d)2:3

A right triangle has perimeter of length 7 and hypotenuse of length 3. If theta is the larger non- right angle in the triangle,then the value of cos theta equal.(sqrt(6)-sqrt(2))/(4) (b) (4+sqrt(2))/(6)(4-sqrt(2))/(3) (d) (4-sqrt(2))/(6)

The ratio of the area of a square of side a and that of an equilateral triangle of side a, is 2:1 (b) 2:sqrt(3)4:3( d) 4:sqrt(3)

If A be the area of a right triangle and b one of the sides containing the right angle,prove that the length of the altitude on the hypotenuse is (2AB)/(sqrt(b^(4)+4A^(2)))

If the sides of a triangle are in the ratio 1 : sqrt3 : 2, then the angles of the triangle are in the ratio