The mean of numbers a,b,8,5,10 is 6 and their variance 6.80 ,then `tan^(-1)((1)/(a))+tan^(-1)((1)/(b))=`

The mean of the number a,b,8,5,10 is 6 and the variance is 6.80 . Then ab =

tan^(-1) (1/5) + tan^(-1) (1/8) =

The value of sec[tan^(-1)((b+a)/(b-a))-tan^(-1)((a)/(b))] is

if a>b>0 then the value of tan^(-1)((a)/(b))+tan^(-1)((a+b)/(a-b)) is

The mean of the numbers a, b, 8, 5, 10 is 6 and the variance is 6.80. Then which one of the following gives possible values of a and b? (1) a""=""0,""b""=""7 (2) a""=""5,""b""=""2 (3) a""=""1,""b""=""6 (4) a""=""3,""b""=""4

[" The mean of the numbers "a,b,8,5,10" is "6" and "],[" the variance is "6.80" .Then which one of the "],[" following gives possible values of "a" and "b" ? "]

2tan^(-1)((1)/(5))+tan^(-1)((1)/(7))+2tan^(-1)((1)/(8))=

2tan^(-1)((1)/(5))+tan^(-1)((1)/(8))= tan^(-1)((4)/(7))

tan^-1 (1/6) + tan^-1 (5/7) = π/4