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Uranium .(92)U^(238) decayed to .(82)Pb^...

Uranium `._(92)U^(238)` decayed to `._(82)Pb^(206)`. They decay process is `._(92)U^(238) underset((x alpha, y beta))(rarr ._(82)Pb^(206))`
`t_(1//2)` of `U^(238) = 4.5 xx 10^(9)` years
The analysis of a rock shows the relative number of `U^(238)` and `Pb^(206)` atoms `(Pb//U = 0.25)` The age of rock will be

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Uranium ._(92)U^(238) decayed to ._(82)Pb^(206) . They decay process is ._(92)U^(238) underset((x alpha, y beta))(rarr ._(82)Pb^(206)) t_(1//2) of U^(238) = 4.5 xx 10^(9) years A sample of rock south America contains equal number of atoms of U^(238) and Pb^(206) . The age of rock will be

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Initially the earth was a fire-ball, slowly it has cooled to form earth crust and its different layers. At the beginning ""_(92)^(238)U was present and no ""_(82)^(206) Pb was there. With the passage of time, uranium decayed to ""_(82)^(206)Pb The decay process is : ""_(92)^(238)U underset((x alpha, y beta))to ""_(82)^(206)Pb , t_(1//2) of ""^(238)U = 4.5 xx 10^(9) yrs A sample of rock from south America contains equal number of atoms of ""^(238)U and ""^(206)Pb . The age of the rock will be :

._(92) U^(238) overset( n alpha n' beta^(0))(to) ._(82) Pb^(206) find n & n

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