If `I_n = int sin^n x \ dx,` then `n I_n - (n-1) I_(n-2)` equals

If I_(n) = int sin^(n)x dx , then nI_(n)-(n-1)I_(n-2)=

If I_n = int sin^n x dx then nI_n - (n - 1)I_(n-2) = f(x)+c where f(x) =

If n in N and I_(n) = intsin^(n) x dx then nI_(n)-(n-1)I_(n-2) =

If I_(n) = int_0^(pi/2) sin^(n)x dx then I_(n)/(I_(n-2)) =

If n(ne 1) in N and I_(n) = int tan^(n) x dx then I_(n)+I_(n-2) =

If n(ne 1) in N and I_(n) =int sec^(n)x dx then (n-1) I_(n)-(n-2)I_(n-2) =

If I_(n)= int(sin nx)/(cos x)dx , then I_(n)=

If I_n = int tan^n x dx , then prove that I_n = (tan^(n-1) x)/(n - 1) - I_(n - 2) . Hence find int tan^7 x dx