A particle when thrown, moves such that it passes from same height at 2 and 10 seconds, then this height h is :

A particle is thrown vertically upwards its velocity at half of the height is 10 m/s then the maximum height attained by it is ( g= 10 m//s^2)

A particle is thrown vertically upward. Its velocity at half of the height is 10 m/s. Then the maximum height attained by it : - (g=10 m//s^2)

A particle is thrown vertically upward. Its velocity at half of the height is 10 m/s. Then the maximum height attained by it : - (g=10 m//s^2)

Two particles begin to fall freely from the same height but the second falls t_(0) second after the first. Find the time (after the dropping of first) when separation between the particles is h_(0) .

A particle is projected vertically upwards and it reaches the maximum height H in time T seconds. The height of the particle at any time t will be-

A particle is projected vertically upwards and it reaches the maximum height H in time T seconds. The height of the particle at any time t will be-

A particle is projected vertically upwards and it reaches the maximum height H in time T seconds. The height of the particle at any time t will be-

A rock of mass m dropped to the ground from a height h. A second rock with mass 2m is dropped from the same height. When second rock strikes the ground, what is its kinetic energy?