The Wave function (Psi) of 2s is given by:
`Psi_(2s)=(1)/(2sqrt2pi)(1/a_(0))^(1//2){2-(r)/a^(0)}e^(-r//2a_(0))`
At `r =r_(0)`, radial node is formed . Thus for 2s `,r_(0),` in terms of `a_(0)` is-

Consider psi (wave function) of 2s atomic orbital of H-atom is- psi_(2s)=(1)/(4sqrt(2pia_(0)^(3//2)))[2-(r )/(a_(0))]e^.(r )/(2a_(0) Find distance of radial node from nucleous in terms of a_(0)

Consider psi (wave function) of 2s atomic orbital of H-atom is- psi_(2s)=(1)/(4sqrt(2pia_(0)^(3//2)))[2-(r )/(a_(0))]e^.(r )/(2a_(0) Find distance of radial node from nucleous in terms of a_(0)

Consider psi (wave function) of 2s atomic orbital of H-atom is- psi_(2s)=(1)/(4sqrt(2pia_(0)^(3//2)))[2-(r )/(a_(0))]e^.(r )/(2a_(0) Find distance of radial node from nucleous in terms of a_(0)

The wave function of 2s electron is given by W_(2s) = (1)/(4sqrt(2pi))((1)/(a_(0)))^(3//2)(2 - (r )/(a_(0)))e^(-1 a0) It has a node at r = r_(p) .Find the radiation between r_(p) and a

The wave function of 3s electron is given by Psi_(3s)=1/(81sqrt(3)prod)(1/a_(0))^(3//2)[27-18(r/a_(0))+2(r/a_(0))^(2)]e^(-r//3a_(0)) It has a node at r=r_(0) , Find out the relation between r_(0) and a_(0)

The wave function of 3s electron is given by Psi_(3s)=1/(81sqrt(3)prod)(1/a_(0))^(3//2)[27-18(r/a_(0))+2(r/a_(0))^(2)]e^(-r//3a_(0)) It has a node at r=r_(0) , Find out the relation between r_(0) and a_(0)

The Schrodinger wave equation for hydrogen atom is Psi_(2s) = (1)/(4sqrt(2pi)) ((1)/(a_(0)))^(3//2) (2 - (r)/(a_(0))) e^(-r//a_(0)) , where a_(0) is Bohr's radius . If the radial node in 2s be at r_(0) , then r_(0) would be equal to :

The Schrodinger wave equation for hydrogen atom is Psi_(2s) = (1)/(4sqrt(2pi)) ((1)/(a_(0)))^(3//2) (2 - (r)/(a_(0))) e^(-r//a_(0)) , where a_(0) is Bohr's radius . If the radial node in 2s be at r_(0) , then r_(0) would be equal to :