In the given figure,`AB" and "CD`are equal chords of a circle with centre O .Prove that `/_AOB~=/_COD` and `/_AOB=/_COD`

In the given figure, AB and CD are two equal chords. If O is the centre of the circle , /_AOB= 120^(@) , then find /_OCD .

In the figure, two equal chords AB and CD of a circle with centre O, intersect each other at E, Prove that AD=CB

AB and CD are equal chords of a circle whose centre is O,when produced these chords meet at E,Prove that EB=ED

In the given figure, chords AB and CD are equal. If angle OBA = 55^(@) then angle COD is :

In the figure,two equal chords AB and CD of a circle with centre O ,intersect each other at E , Prove that AD=CB

O is the centre of a circle.AC and BD are two chords of the circle intersecting each other at P.If /_AOB=15^(@) and /_APB=30^(@), then 3(tan^(2)/_APB+cot^(2)/_COD) is equal to

In the given figure, AB||CD and AB=CD , prove that: triangle AOB is congruent to triangle DOC.

In the adjoining figure, O is the centre of the circle. AB is an arc of the circle and /_AOB=80^(@) . Find /_ACB .