A unifrom rod of length `l` and mass `m` is free to rotate in a vertical plane about `A`, Fig. The rod initially in horizontal position is released. The initial angular acceleration of the rod is `(MI "of rod about" A "is" (ml^(2))/(3))`

A unifrom rod of length l and mass m is free to rotate in a vertical plane about A as shown in Fig. The rod initially in horizontal position is released. The initial angular acceleration of the rod is

A uniform rod of length l and mass m is free to rotate in a vertical plane about A as shown in Fig. The rod initially in horizontal position is released. The initial angular acceleration of the rod is

A uniform rod of mass m and length L is free to rotate in the vertical plane about a horizontal axis passing through its end. The rod initially in horizontal position is released. The initial angular acceleration of the rod is:

A uniform rod of length L and mass M is free to rotate about a frictionless pivot at one end. The rod is released from rest in the horizontal position. What are the initial angular acceleration of the rod and the initial linear acceleration of the right end of the Rod ?

A uniform rod of length l and mass M pivoted about its end as shown in Fig. and is free to rotate in the vertical plane about the pivot. The rod is released from rest in the horizontal position. (a) What is the initial angular acceleration of the rod? (b) Find the initial acceleration of the right end of the rod? ( c) Find normal contact force due to hinge when rod has rotated through angle theta as shown in Fig.

A uniform rod AB of length L and and weight Mg is hinged at one end A. The rod is kept in the horizontal position by a massless string. If the string is cut, then the angular acceleration of the rod will be ["M.I. of the rod about A is "(ML^(2))/(3)]

A uniform rod of length L is free to rotate in a vertical plane about a fixed horizontal axis through B . The rod begins rotating from rest. The angular velocity omega at angle theta is given as

A unifrom rod AB of length l,and mass m is free to rotate about point A.The rod is release from rest in the horizontal position Given that the moment of inertia of the rod about A is (ml^2)/3 , the initial angular acceleration of the rod will be: