Figure shows the variation of electric field intensity E versus distance x. The magnitude potential difference between the point at x = 0 to x = 6 m will be

Figure shows the variation of electric field intensity E with distance x. The potential difference between the point x = 0 and x= 5m is

Show that the electric field intensity at a point can be given as negative of potential gradient.

If the electric field is given by vec(E ) = ((100)/(x^(2)))i the potential difference between points x=10m and x=20m in volts is

Electric field at a distance x from the origin is given as E =(100N-m^2//C)/x^2 . Then potential difference between the points situated at x = 10 m and x = 20m is :-

Deduce the relation between electric field intensity and potential at a point in an electric field.

Draw a plot showing the variation of (i) electric field (E ) and (ii) electric potential (V) with distance r due to a point charge Q.