If `cos^2theta/2=sin^2theta/3` find `cos^4theta/2+sin^4theta/3`

If (cos^(2)theta)/(2)=(sin^(2)theta)/(3) find (cos^(4)theta)/(2)+(sin^(4)theta)/(3)

If cos^4theta-sin^4theta=2/3 then 2cos^2theta-1=

sin^2theta+cos^4theta=cos^2theta+sin^4theta

If (cos^(2)theta)/(2)=(sin^(2)theta)/(3), then find (cos^(4)theta)/(2)+(sin^(4)theta)/(3)

If cos^(4)theta-sin^(4)theta=(2)/(13) , find cos^(2)theta-sin^(2)theta+1 .

Prove the following sin^4theta-cos^4theta=sin^2theta-cos^2theta=1-2cos^2theta=2sin^2theta-1

Prove that-: cos^4theta/(1-sin^4theta)=(1-sin^2theta)/(1+sin^2theta)

We express ((cos 2theta -i sin 2theta)^(4) (cos 4theta + i sin 4 theta)^(-5))/((cos 3theta + i sin 3theta)^(-2) (cos 3theta -i sin 3theta)^(-9)) in the form of x+iy , we get

The value of (2(sin^6 theta+cos^6 theta)-3(sin^4 theta+cos^4 theta))/ (cos^4 theta-sin^4 theta-2cos^2 theta) is (2(sin^6 theta+cos^6 theta)-3(sin^4 theta+cos^4 theta))/ (cos^4 theta-sin^4 theta-2cos^2 theta) का मान है: