Heat of neutralisation for the reaction:
`NaOH+HCl to NaCl+H_(2)O`
is 57.1 kJ `mol^(-1)`. The heat released when 0.25 mole of NaOH is titrated against 0.25 mole of HCl will be:

Heat of neutralisation for the reaction NaOH + HCl rarr NaCl + H_(2)O " is " -57.1 kJ "mole"^(-1) . The heat relased when 0.25 moles of NaOH is treated with 0.25 moles of HCl is

Heat of neutralization of the reaction, NaOH+HCl rarr NaCl + H_(2)O is 57.2"kJ mol"^(-1) . What will be the heat released when 0.25 mole of NaOH is titrated against 0.25 mole of HCl

Heat of neutralization for the reaction, is 57.1kJ mol^(−1) . The heat released when 0.25 mole of NaOH is titrated against 0.25 mole HCl will be: NaOH+HCl→NaCl+H_2O

The heat of neutralisation of a strong acid and a strong alkali is 57.0kJ mol ^(-1). The heat released when 0.2 mole of HNO_(3) soluton is mixed with 0.2 mole of KHO is

The heat of neutralisation of a strong acid and a strong alkali is 57.0KJ mol^(-1) . The heat released when 0.5 mole of HNO_(3) solution is mixed with 0.2 mole of KOH is