Position of a particle varies as `y = cos^(2) omegat - sin^(2) omegat`. It is

A particle m starts with zero velocity along a line y=4d . The position of particle m varies as x=A sin omegat , At omegat=pi//2 , its angular momentum with respect to the origin

A particle m starts with zero velocity along a line y=4d . The position of particle m varies as x=A sin omegat , At omegat=pi//2 , its angular momentum with respect to the origin

Show that the motion of a particle represented by y = sin omega t - cos omegat is simple harmonic with a period of 2pi//omega .

The position vector of a particle is vecr = (a cos omega t)hati + (a sin omegat)hatj . the velocity of the particle is

The displacement of a particle is given by r = A (cos omegat hati + sin omegat hatj ) . The motion of the particle

The motion of a particle is given by x=A sin omegat+Bcos omegat . The motion of the particle is

The motion of a particle is given by x=A sin omegat+Bcos omegat . The motion of the particle is