The displacement (from intial position) of a particle executing `SHM` with amplitude `A` in half the time period is always

The displacement from mean position of a particle in SHM at 3 seconds is sqrt(3) /2 of the amplitude. Its time period will be :

The KE and PE , at is a particle executing SHM with amplitude A will be equal when its displacement is

The KE and PE , of a particle executing SHM amplitude A will be equal when its displacement is

The KE and PE , at is a particle executing SHM with amplitude A will be equal when its displacement is

The KE and PE of a particle executing SHM of amplitude a will be equal when displacement is:

Velocity at mean position of a particle executing S.H.M. is v , they velocity of the particle at a distance equal to half of the amplitude

A particle executes SHM with amplitude A and time period T. When the displacement from the equilibrium position is half the amplitude , what fractions of the total energy and kinetic and potential?

A particle executes SHM with amplitude A and time period T. When the displacement from the equilibrium position is half the amplitude , what fractions of the total energy are kinetic and potential energy?

Velocity at mean position of a particle executing SHM is v. Velocity of the particle at a distance equal to half of the amplitude will be