The equation `sin^(-1) x = 2 sin^(-1) alpha` has a solution

If sin^(-1)x = 3 sin^(-1) alpha has a solution then :

If sin^(-1)x=2sin^(-1)alpha has a solution, then

The trigonometric equation sin^(-1) x=2 sin^(-1) a has a solution for :

The trigonometric equation sin^(-1)x=2sin^(-1)a has a solution for

The equation sin^(-1)x - 3sin^(-1)a =0 has real solutions for x if

The trigonometric equation sin^(-1)x=2 sin^(-1)2a has a real solution, if

Assertion A : The equation sin^(-1)x=3sin^(-1)(a) has a solution for -1/2leale1/2 Reason : AA x in [-1,1], sin^(-1)x in [0,2pi]