Home
Class 11
PHYSICS
Pressure depends on distance as, P = (al...

Pressure depends on distance as, `P = (alpha)/(beta)exp((-alpha z)/(k theta))`, where `alpha, beta` are constants, z is distance, k is Boltzmann's constant and `theta` is temperature. The dimensions of `beta` are :

Promotional Banner

Similar Questions

Explore conceptually related problems

Pressure depends on distance as, P = (alpha)/(beta)exp(-(alphaz)/(ktheta)) , where alpha, beta are constants, z is distance as , k is Boltzman's constant and theta is tempreature. The dimension of beta are

Pressure depends on distance as P =(alpha)/(beta) "exp" (-(alphaz)/(ktheta)) where alpha beta are constants z is distance k is Boltzmann is constant and theta is temperature. The dimension of beta are

In the releation p=(alpha)/(beta) e^(-)(az)/(ktheta) , where p is the pressure z is distance k is Boltzmann constant and theta is the temperature the dimensional formula beta will be

In the relation: P=(alpha)/(beta)e^(-(alphaZ)/(ktheta)),P is pressure Z is distance k is Boltzmann constant and theta is the temperature. The dimensional formula of beta will be

In the relation: P=(alpha)/(beta)e^(-(alphaZ)/(ktheta)),P is pressure Z is distance k is Boltzmann constant and theta ils the temperature. The dimensional formula of beta will bes

In the relation: P=(alpha)/(beta)e^(-(alphaZ)/(ktheta)),P is pressure Z is distance k is Boltzmann constant and theta ils the temperature. The dimensional formula of beta will bes