The equation of a wave is given by `Y = A sin omega((x)/(v) -k)`
where `omega` is the angular velocity and v is the linear velocity. The dimension of k is

The equation of a wave is given by Y = A sin omega ((x)/(v) - k) , where omega is the angular velocity and v is the linear velocity. Find the dimension of k .

The equation of a wave is given by Y = A sin omega ((x)/(v) - k) , where omega is the angular velocity and v is the linear velocity. Find the dimension of k .

The equation of a wave is given by Y = A sin omega ((x)/(v) - k) , where omega is the angular velocity and v is the linear velocity. Find the dimension of k .

The equation of a wave is given by Y = A sin omega ((x)/(v) - k) , where omega is the angular velocity and v is the linear velocity. Find the dimension of k .

The equation of a wave is given by y = a sin omega [(x)/v -k] where omega is angular velocity and v is the linear velocity . The dimensions of k will be

The equation of a wave is given by y = a sin omega [(x)/v -k] where omega is angular velocity and v is the linear velocity . The dimensions of k will be

The equation of a wave is given by y = a sin omega [(x)/v -k] where omega is angular velocity and v is the linear velocity . The dimensions of k will be

The linear velocity of a rotating body is given by v =omega xx r , where omega is the angular velocity and r is the radius vector. The angular velocity of a body omega=hati-2hatj+2hatk and their radius vector r=4hatj-3hatk, |v| is -

Given below is an equation of a wave: y = r sin omega (x//v - kpi) . What are the dimensions of x and k? Here omega is angular velocity and v linear velocity.

The linear velocity of a rotating body is given by vec(v)= vec(omega)xxvec(r ) , where vec(omega) is the angular velocity and vec(r ) is the radius vector. The angular velocity of a body is vec(omega)= hat(i)-2hat(j)+2hat(k) and the radius vector vec(r )= 4hat(j)-3hat(k) , then |vec(v)| is