In fig. AB and CD are two equal chords of a circle with centre O. OP and OQ are perpendiculars on chords AB and CD respectively. If `anglePOQ=150^(@)` then `angleAPQ` is equal to

In AB and CD are two equal chords of a circle with center O. OP and OQ are perpendiculars on chords AB and CD respectively. If anglePOQ=150^(@) then angleAPQ is equal to

AB and CD are equal chords of a circle whose center is O,

AB and CD are two chords of circle with centre O and are perpendicular to each other. If angleOAC=25^(@) then angleBCD = ?

In the given figure, AB and CD are two equal chords of a circle, with centre O. If P is the mid-point of chord AB, Q is the mid-point of chord CD and anglePOQ = 150^(@) find angleAPQ

AB and CD are equal chords of a circle whose centre is O,when produced these chords meet at E,Prove that EB=ED

In the given figure, AB" and "CD are equal chords of a circle with centre O .Prove that /_AOB~=/_COD and /_AOB=/_COD

AB and CD are two equal chords of a circle with centre at O. If the distacne of AB form O be 2 cm , then find the distance of CD form O.

AB and CD are equal and parallel chords of a circle with centre O. Then AC passes through the centre O. [Agree // Disagree]

L and M are mid-points of two equal chords AB and CD of a circle with centre O Prove that angleALM = angleCML