In Fig. 3, the area of triangle ABC (in sq. units) is :

Area of triangle = ………….sq. units .

Let A=(4, 0), B=(0, 12) be two points in the plane. The locus of a point C such that the area of triangle ABC is 18 sq. units is -

A(0,sqrt(2))andB(2sqrt(2),0) are two vertices of a triangle ABC and AB=BC . If the equation of the side BC be x=2sqrt(2) , then the area of triangle ABC is (in sq . Units )-

In a triangle ABC, points P, Q and R are the mid-points of the sides AB, BC and CA respectively. If the area of the triangle ABC is 20 sq. units, find the area of the triangle PQR

IF 13,14,15 are the sides of the triangle , then the area of the triangle in sq. unit is

ABC is a triangle where a=6, b=3 and cos(A-B)=4/5 (i) Area of the triangle ABC (in sq. units) is-

The area of below triangle is….sq.units.

The area of the triangle BOA is .......sq. units .