Solutions Of Triangle

Basic introduction OF Solution OF Triangle

Solution of Triangle in different cases :- (5) When b>c sin B;c c;B=90^(@) (7) b>c;B=90^(@)(8)b<=c and B=90^(@)

Solution of Triangle in different cases :- (1) When bltcsinB (2) b=csinB and B is an acute angle (3)bgtcsinB;bltc and B is an acute angle (4) bgtcsinB;cltb;and B is an acute angle

In the ambiguous case of the solution of triangle, prove that the circumcircles of the two triangles are of same size.

If alpha,beta,gamma are the angles of a triangle and system of equations cos(alpha-beta)x+cos(beta-gamma)y+cos(gamma-alpha)z=0 cos(alpha+beta)x+cos(beta+gamma)y+cos(gamma+alpha)z=0 sin(alpha+beta)x+sin(beta+gamma)y+sin(gamma+alpha)z=0 has non-trivial solutions, then triangle is necessarily a. equilateral b. isosceles c. right angled "" d. acute angled

If alpha,beta,gamma are the angles of a triangle and system of equations cos(alpha-beta)x+cos(beta-gamma)y+cos(gamma-alpha)z=0cos(alpha+beta)x+cos(beta+gamma)y+cos(gamma+alpha)z=0sin(alpha+beta)x+sin(beta+gamma)y+sin(gamma+alpha)z=0 has non-trivial solutions,then triangle is necessarily a.equilateral b.isosceles c.right angled

If alpha,beta,gamma are the angles of a triangle and system of equations cos(alpha-beta)x+cos(beta-gamma)y+cos(gamma-alpha)z=0 cos(alpha+beta)x+cos(beta+gamma)y+cos(gamma+alpha)z=0 sin(alpha+beta)x+sin(beta+gamma)y+sin(gamma+alpha)z=0 has non-trivial solutions, then triangle is necessarily a. equilateral b. isosceles c. right angled "" d. acute angled

If alpha,beta,gamma are the angles of a triangle and system of equations cos(alpha-beta)x+cos(beta-gamma)y+cos(gamma-alpha)z=0 cos(alpha+beta)x+cos(beta+gamma)y+cos(gamma+alpha)z=0 sin(alpha+beta)x+sin(beta+gamma)y+sin(gamma+alpha)z=0 has non-trivial solutions, then triangle is necessarily a. equilateral b. isosceles c. right angled "" d. acute angled

Let Delta=|(1,-4,20),(1,-2,5),(1,2,5x^(2))| Solution set of Delta=0 is