Sum of the series `1+2.2+3.2^2 +4.2^3+.....+100.2^99` is

1+2.2+3.2^2+4.2^3+....100.2^99 equals

The sum of the series 1 + 2.2 + 3.2^(2) + 4.2^(3) + 5.2^(4) + ……… + 100.2^(99) is

. Find the sum of the series 1.2+2.2^(2)+3.2^(2)+...+100.2^(100)

Find the sum of the series: 1^2-2^2+3^2-4^2+.....-2008^2+2009^2 .

Sum of 25 terms of the series 1+2 . 2+3 . 2^(2)+4 . 2^(3)+5 . 2^(4)+..

"The sum of the series, 1/ 2.3 ⋅ 2 + 2/ 3.4 ⋅ 2^ 2 + 3/ 4.5 ⋅ 2^ 3 + ... ... . . to n terms is

The sum to 100 terms of the series 1.2.3. + 2.3.4. + 3.4.5. + …+ n(n + 1) (n+2) + …. is integral multiple of

The sum to 100 terms of the series 1.2.3. + 2.3.4. + 3.4.5. + …+ n(n + 1) (n+2) + …. is integral multiple of

The sum of the series, (1)/(2.3) .2 + (2)/(3.4).2^(2) + (3)/(4.5).2^(3) + ….to n terms is