A body starts to fall freely under gravity. The distances covered by it in first, second and third second are in ratio

A stone at rest is dropped from a height and falls freely under gravity. Calculate the distance covered by it in the first two seconds. (g = 9.8 m s^(-2) )

A ball falls freely from rest. The ratio of the distance travelled in first, second, third and fourth second is

A ball falls freely from rest. The ratio of the distance travelled in first, second, third and fourth second is

The distance travelled by a body falling from reset in the frist, second and third seconds are in the ratio

A stone falls freely rest. The distance covered by it in the last second is equal to the distance covered by it in the first 2 s. The time taken by the stone to reach the ground is

A stone falls freely rest. The distance covered by it in the last second is equal to the distance covered by it in the first 2 s. The time taken by the stone to reach the ground is

" The distances traveled by a body falling freely from rest in the first,second and third seconds are in the ratio "

A stone falls freely under gravity . It covers distances h_1 h_2 and h_3 in the first 5 seconds , the next 5 seconds and the next 5 seconds respectively . The relation between h_1 , h_2 and h_3 is: