`16x^(7)-81x^(3)-16x^(4)+81`

x^(7)+x^(4)-16x^(3)-16

Factorize: x^(4)-y^(4) (ii) 16x^(4)-81x^(4)-(y+z)^(4)( iv )2x-32x^(5)3a^(4)-48b^(4)(vi)81x^(4)-121x^(2)

Factorise: (i) 3x^(7)y -81x^(4)y^(4) (ii) a^(3) + 0.064

Solve the equation : 3x^(4)-16x^(3)+26x^(2)-16x+3=0

The HCF of 8x^(4) - 16x^(3) - 40x^(2) + 48x and 16x^(5) + 64x^(4) + 80x^(3) + 32x^(2) is

If two roots of x^(4) - 16x^(3) + 86x^(2) - 176x + 105 = 0 are 1, 7 then the roots are

(81x^(2)-81)-:(x+1)

Simplify (81x^(4)-16x^(2)+32x-16)/(9x^(2)-4x+4)

Simplify (81x^(4)-16x^(2)+32x-16)/(9x^(2)-4x+4)

If x=3 and y=-1, find the values of each of the using identity: (9y^(2)-4x^(2))(81y^(4)+36x^(2)y^(2)+16x^(4))