The work done by the force `= vec F = A (x^(2) hati + 2 x^(2) hatj)`, where A is a constant and x and y are in meters around the path shown is.

The work done by the force = vec F = A (y^(2) hati + 2 x^(2) hatj) , where A is a constant and x and y are in meters around the path shown is.

The work done by the force vec(F)=A(y^(2) hati+2x^(2)hatj) , where A is a constant and x & y are in meters around the path shown is :

The work done by the force vec(F)=A(y^(2) hati+2x^(2)hatj) , where A is a constant and x & y are in meters around the path shown is :

A particle is moved along a path AB - BC - CD - DE - EF - FA , as shown in figure, in presence of a force vecF = (alpha y hati + 2 alpha xhatj)N , where x and y are in meter and alpha = -1Nm^(-1) . The work done on the particle by this by this force will be Joule.

A force F=-k(^hati + x^hatj) (where k is a positive constant) acts on a particle moving in the x-y plane. Starting from the origin, the particle is taken along the positive x-axis to the point (a,0) and then parallel to the y-axis to the point (a,a) . The total work done by the force F on the particle is (a) -2ka^(2) , (b) 2ka^(2) , (c) -ka^(2) , (d) ka^(2)

A force F=-k(^hati + x^hatj) (where k is a positive constant) acts on a particle moving in the x-y plane. Starting from the origin, the particle is taken along the positive x-axis to the point (a,0) and then parallel to the y-axis to the point (a,a) . The total work done by the force F on the particle is (a) -2ka^(2) , (b) 2ka^(2) , (c) -ka^(2) , (d) ka^(2)

The work done by a force vec(F)=(-6x^(3)hat(i)) N in displacing a particle from x = 4m to x = - 2m is

The work done by a force vec(F)=(-6x^(3)hat(i)) N in displacing a particle from x = 4m to x = - 2m is

The work done by an applied variable force F=x+x^(3) from x = 0 m to x = 2m, where x is displacement, is