सिद्ध कीजिए कि :
`a+(a+d)+(a+2d)+…+[a+(n-1)d]=(n)/(2)[2a+(n-1)d]`.

By the Principle of Mathematical Induction, prove the following for all n in N : a+ (a+d)+(a+2d)+....+ [a+(n-1)d] =n/2 [2a + (n-1)d] .

Prove the following by using the principle of mathematical induction for all n in N a + (a+d)+(a+2d) +……+ (a+(n-1)d) = n/2 [2a + (n-1)d]

Statement-1: 1+2+3....+n=(n(n+1))/(2),"for all "n in N Statement-2: a+(a+d)+(a+2d)+....+(a+(n-1)d)=(n)/(2)[2a+(n-1)d]

Statement-1: 1+2+3....+n=(n(n+1))/(2),"for all "n in N Statement-2: a+(a+d)+(a+2d)+....+(a+(n-1)d)=(n)/(2)[2a+(n-1)d]

Prove the following by the principle of mathematical induction: a+(a+d)+(a+2d)++(a+(n-1)d)=(n)/(2)[2a+(n-1)d]

Statement-1: The sum of n terms of the series a+(a+d)+(a+2d)+...(a+(n-1)d)=(n)/(2)[2a+(n-1)d] Statement-2:- Mathematical induction is valid only for natural numbers.

Statement-1: The sum of n terms of the series a+(a+d)+(a+2d)+...(a+(n-1)d)=(n)/(2)[2n+(n-1)d] Statement-2:- Mathematical induction is valid only for natural numbers.

Prove the following by the principle of mathematical induction: a+(a+d)+(a+2d)++(a+(n-1)d)=n/2[2a+(n-1)d]

For all ninNN , prove by principle of mathematical induction that, a+(a+d)+(a+2d)+ . . . to n terms =(n)/(2)[2a+(n-1)d] .