A particle of mass `0.6g` and having charge of `25 n_(C)` is moving horizontally with a uniform velocity `1.2xx10^(4)ms^(-1)` in a uniform magnetic field, then the value of the magnetic induction is `(g=10ms^(-2))`

A particular of mass 0.6 g and having charge of 25 nC is moving horizontally with a uniform velocity 1.2xx10^(4) ms^(-1) in a uniform magnetic induction is ( g=10 ms^(-2) )

An electron is moving northwards with a velocity 3*0xx10^7ms^-1 in a uniform magnetic field of 10T directed eastwards. Find the magnitude and direction of the magnetic force on the electron. (e=1*6xx10^(-19)C)

A particle of mass 2 kg charge 1 mC is projected vertially with velocity k 10 ms^-1 . There is as uniform horizontal electric field of 10^4N//C, then

A particle of mass 3 xx 10^(-6)g has the same wavelength as an electron moving with a velocity 6 xx 10^(6) ms^(-1) . The velocity of the particle is

A particle of mass 2 kg chrge 1 mC is projected vertially with velocity k 10 ms^-1 . There is as uniform horizontal electric field of 10^4N//C, then

A particle of mass 2 kg chrge 1 mC is projected vertially with velocity k 10 ms^-1 . There is as uniform horizontal electric field of 10^4N//C, then

A particle of mass 2 kg chrge 1 mC is projected vertially with velocity k 10 ms^-1 . There is as uniform horizontal electric field of 10^4N//C, then

A particle of mass 0.5 gm and charge 2.5xx10^(-8) coulomb is moving with velocity 6xx10^(4)m//s , horizontally what should be the value of magnetic field acting on it so that the particle is able to move in a straight line - (g=9.8m//s^(2))

A straight wire of mass 150 g and length 2 m carries a current of 1.5 A. It is suspended in mid-air by a uniform horizontal magnetic field B (figure). What is the magnitude of the magnetic field ? (g=10ms^(-2))