The equation of the plane which bisects the line joining `(2, 3, 4)` and `(6,7,8)`

The equation of a plane which bisects the line joining (1, 5, 7) and (-3, 1, -1) is x+y+2z=lambda , then lambda must be…..

The equation of a plane which bisects the line joining (1, 5, 7) and (-3, 1, -1) is x+y+2z=lambda , then find lambda .

The equation of a plane which bisects the line joining (1, 5, 7) and (-3, 1, -1) is x+y+2z=lambda , then find lambda .

The equation of the plane, which bisects the line joining the points (1, 2, 3) and (3, 4, 5) at right angles, is

Find the equation of the plane, which bisects the line joining the points (-1,2,3) and (3,-5,6) ate right angles.

Equation of the plane which bisects the line segment joining (-1,2,3) and (3,-5,6) perpendicularly, is

Find the equation of the plane bisecting the line segment joining (2, 0, 6) and (-6, 2, 4) and perpendicular to it.