A 1 `mu` C charge is uniformly distributed on a spherical shell given by the equation `x^(2)+y^(2)+z^(2)=25 `.
What will be the intensity of electric field at a point (1,1,2) ?

Electric potential in a region of space is given by V=(x^(2)+y^(2)+z^(2))V . What will be electric field intensity at a point P(-1m, 2m, -3m)?

" In a region of space,potential function is given by V=y^(2)+2.5xy-3.5xyz " volt.Then intensity of electric field at a point " (x=1m,y=1m,z=1m) " is "

Electric potential in a region is given by V=12x^(2)+3y^(2)+z^(2) . Calculate the electric field intensity at point (1m, 3m, 2m).

Given: electric potential, phi = x^(2) + y^(2) +z^(2) . The modulus of electric field at (x, y, z) is

A force of 2.25 N acts on a charge of 15xx10^(-4)C . The intensity of electric field at that point is

In a certain region of space, the potential is given by V=k(2x^(2)-y^(2)+z^(2)) . The electric field at the point (1, 1, 1) has magnitude:

A thin non-conducting hemispherical shell contains a positive charge q on it, which uniformly distributed on the shell. A point P lies on the diameter of shell as show in figure. Then the direction of electric field at the point 'P' is

Electric potential in space V(x,y,z) = (x^(2) + y^(2) + z^(2))V Then the magnitude of electric field strength E at (1m, 0, 2m) in N/C is:

A charge Q is uniformly distributed on a thin spherical shell. What is the field at the centre of the shell? If a point charge is brought close to the shell, will the field at the centre change? Does your answer depend on whether the shell is conducting or nonconducting?

The electric potential V at any point (x, y) in a plane is given by V=5x^(2)-4y^(2) volt. Find the magnitude of electric field intensity at the point (1m, 2m).